由于第一列的雷可能有多种方案满足第二列的数的限制,你的任务即根据第二列的信息确定第一列雷有多少种摆放方案,第一行为$$n$$,第二行有$$n$$个数,依次为第二列的格子中的数。
相信大家都玩过扫雷的游戏。那是在一个方格阵里面有一些雷,要你根据格子中的数字找出雷来。dotcpp跨年时某管理整了一个~~好活~~游戏,这个游戏规则和扫雷一样,如果某个格子没有雷,那么它里面的数字表示和它$$8$$相邻的格子里面雷的数目。现在棋盘是$$ntimes 2$$的,第一列里面某些格子是雷,而第二列没有雷,如下图: ![](https://blog.dotcpp.com/ueditor/php/upload/image/20210828/1630135116509795.png) 由于第一列的雷可能有多种方案满足第二列的数的限制,你的任务即根据第二列的信息确定第一列雷有多少种摆放方案。 第一行为$$n$$,第二行有$$n$$个数,依次为第二列的格子中的数。 输出一个数,即第一列中雷的摆放方案数。 2 1 1 2 对于$$100%$$的数据:$$1 le n le 10000$$ ## 数据制造者
相信大家都玩过扫雷的游戏。那是在一个方格阵里面有一些雷,要你根据格子中的数字找出雷来。dotcpp跨年时某管理整了一个好活游戏,这个游戏规则和扫雷一样,如果某个格子没有雷,那么它里面的数字表示和它888相邻的格子里面雷的数目。现在棋盘是n×2ntimes 2n×2的,第一列里面某些格子是雷,而第二列没有雷,如下图: 由于第一列的雷可能有多种方案满足第二列的数的限制,你的任务即根据第二列的信息确定第一列雷有多少种摆放方案。 .katex { font-size: 1.4em!important; } @font-face { font-family: 'KaTeX_AMS'; src: url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_AMS-Regular.woff2) format('woff2'), url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_AMS-Regular.woff) format('woff'), url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_AMS-Regular.ttf) format('truetype'); font-weight: normal; font-style: normal; } @font-face { font-family: 'KaTeX_Caligraphic'; src: url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_Caligraphic-Bold.woff2) format('woff2'), url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_Caligraphic-Bold.woff) format('woff'), url(https://cdn.jsdelivr.net/npm/katex@0.12.0/dist/fonts/KaTeX_Caligraphic-Bold.ttf) format('truetype'); font-weight: bold; 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font-weight: normal; font-style: normal; } var box = new Array(); $(function() { var _list = document.getElementsByClassName("panel_prob_body") for (i = 1; i <= 5; ++i) { _list[i].id = "box" + i; if (i == 3 || i == 4) { _list[i].innerHTML = "" + $("#text" + i).text() + "" } else { _list[i].innerHTML = "" } } for (i = 0; i <= 5; ++i) { // alert(i); if (i == 3 || i == 4) { continue; } else { box[i] = editormd.markdownToHTML("box" + i, { markdown : $("#text" + i).text(), htmlDecode : "style,script,iframe", // you can filter tags decode tocm : true, emoji : true, taskList : true, tex : true, // 默认不解析 flowChart : true, // 默认不解析 sequenceDiagram : true, // 默认不解析 }); } } // document.body.scrollTop = 0; // document.documentElement.scrollTop = 0; }); 想要在职场中立于不败之地?那就来试试全网最全C++题库,让您在练习中快速提升技能。
标签: 编程练习 基础2555: 扫雷题解